Base | Representation |
---|---|
bin | 100111110101101101000… |
… | …0100101100110000000111 |
3 | 201101110002022112012122222 |
4 | 1033223122010230300013 |
5 | 1204202203413000241 |
6 | 15351215143442555 |
7 | 1103405452403366 |
oct | 117533204546007 |
9 | 21343068465588 |
10 | 5475447000071 |
11 | 18211400a5784 |
12 | 74521815645b |
13 | 309442494bc9 |
14 | 14d027b3d7dd |
15 | 97667a2ba4b |
hex | 4fada12cc07 |
5475447000071 has 2 divisors, whose sum is σ = 5475447000072. Its totient is φ = 5475447000070.
The previous prime is 5475447000059. The next prime is 5475447000103. The reversal of 5475447000071 is 1700007445745.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5475447000071 - 230 = 5474373258247 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5475446999986 and 5475447000031.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5475447000031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2737723500035 + 2737723500036.
It is an arithmetic number, because the mean of its divisors is an integer number (2737723500036).
Almost surely, 25475447000071 is an apocalyptic number.
5475447000071 is a deficient number, since it is larger than the sum of its proper divisors (1).
5475447000071 is an equidigital number, since it uses as much as digits as its factorization.
5475447000071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 548800, while the sum is 44.
The spelling of 5475447000071 in words is "five trillion, four hundred seventy-five billion, four hundred forty-seven million, seventy-one", and thus it is an aban number.
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