Base | Representation |
---|---|
bin | 100111110101101101000… |
… | …0100101100110000100111 |
3 | 201101110002022112012201011 |
4 | 1033223122010230300213 |
5 | 1204202203413000403 |
6 | 15351215143443051 |
7 | 1103405452403443 |
oct | 117533204546047 |
9 | 21343068465634 |
10 | 5475447000103 |
11 | 18211400a5803 |
12 | 745218156487 |
13 | 309442494c22 |
14 | 14d027b3d823 |
15 | 97667a2ba6d |
hex | 4fada12cc27 |
5475447000103 has 2 divisors, whose sum is σ = 5475447000104. Its totient is φ = 5475447000102.
The previous prime is 5475447000071. The next prime is 5475447000119. The reversal of 5475447000103 is 3010007445745.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5475447000103 - 25 = 5475447000071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5475447000193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2737723500051 + 2737723500052.
It is an arithmetic number, because the mean of its divisors is an integer number (2737723500052).
Almost surely, 25475447000103 is an apocalyptic number.
5475447000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
5475447000103 is an equidigital number, since it uses as much as digits as its factorization.
5475447000103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 235200, while the sum is 40.
The spelling of 5475447000103 in words is "five trillion, four hundred seventy-five billion, four hundred forty-seven million, one hundred three", and thus it is an aban number.
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