Base | Representation |
---|---|
bin | 11000111011011000000110… |
… | …01011001110101011110111 |
3 | 21012002102112112021010101211 |
4 | 30131230003023032223313 |
5 | 24141104121020433411 |
6 | 312330242014102251 |
7 | 14355243305340601 |
oct | 1435540313165367 |
9 | 235072475233354 |
10 | 54816720874231 |
11 | 16514705956778 |
12 | 6193a20aaa987 |
13 | 247826b6bb9a4 |
14 | d77201890171 |
15 | 650d96d4a221 |
hex | 31db032ceaf7 |
54816720874231 has 2 divisors, whose sum is σ = 54816720874232. Its totient is φ = 54816720874230.
The previous prime is 54816720874177. The next prime is 54816720874343. The reversal of 54816720874231 is 13247802761845.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54816720874231 is a prime.
It is a super-3 number, since 3×548167208742313 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54816720874031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27408360437115 + 27408360437116.
It is an arithmetic number, because the mean of its divisors is an integer number (27408360437116).
Almost surely, 254816720874231 is an apocalyptic number.
54816720874231 is a deficient number, since it is larger than the sum of its proper divisors (1).
54816720874231 is an equidigital number, since it uses as much as digits as its factorization.
54816720874231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18063360, while the sum is 58.
The spelling of 54816720874231 in words is "fifty-four trillion, eight hundred sixteen billion, seven hundred twenty million, eight hundred seventy-four thousand, two hundred thirty-one".
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