Base | Representation |
---|---|
bin | 11000111011111011011010… |
… | …11000010100101011100101 |
3 | 21012011020111000000121022101 |
4 | 30131331231120110223211 |
5 | 24141411434213420431 |
6 | 312343055332532101 |
7 | 14356514222121505 |
oct | 1435755530245345 |
9 | 235136430017271 |
10 | 54835682560741 |
11 | 16521756273475 |
12 | 6197633181031 |
13 | 2479ca0c33434 |
14 | d780bdcd3a05 |
15 | 651606867961 |
hex | 31df6d614ae5 |
54835682560741 has 2 divisors, whose sum is σ = 54835682560742. Its totient is φ = 54835682560740.
The previous prime is 54835682560697. The next prime is 54835682560853. The reversal of 54835682560741 is 14706528653845.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32133592822500 + 22702089738241 = 5668650^2 + 4764671^2 .
It is a cyclic number.
It is not a de Polignac number, because 54835682560741 - 213 = 54835682552549 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54835682560441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27417841280370 + 27417841280371.
It is an arithmetic number, because the mean of its divisors is an integer number (27417841280371).
Almost surely, 254835682560741 is an apocalyptic number.
It is an amenable number.
54835682560741 is a deficient number, since it is larger than the sum of its proper divisors (1).
54835682560741 is an equidigital number, since it uses as much as digits as its factorization.
54835682560741 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 193536000, while the sum is 64.
The spelling of 54835682560741 in words is "fifty-four trillion, eight hundred thirty-five billion, six hundred eighty-two million, five hundred sixty thousand, seven hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •