Base | Representation |
---|---|
bin | 100111111001101011010… |
… | …0001010011110101111110 |
3 | 201102021002210211122220111 |
4 | 1033303112201103311332 |
5 | 1204322141143412300 |
6 | 15355145430140234 |
7 | 1104130033104214 |
oct | 117632641236576 |
9 | 21367083748814 |
10 | 5483977325950 |
11 | 1824818262882 |
12 | 7469b8ab167a |
13 | 30a1a184a506 |
14 | 14d5d6a14cb4 |
15 | 979b68809ba |
hex | 4fcd6853d7e |
5483977325950 has 48 divisors (see below), whose sum is σ = 10353269312640. Its totient is φ = 2160677581920.
The previous prime is 5483977325881. The next prime is 5483977325951. The reversal of 5483977325950 is 595237793845.
It is a Harshad number since it is a multiple of its sum of digits (67).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5483977325951) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 46717431 + ... + 46834669.
It is an arithmetic number, because the mean of its divisors is an integer number (215693110680).
Almost surely, 25483977325950 is an apocalyptic number.
5483977325950 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
5483977325950 is a deficient number, since it is larger than the sum of its proper divisors (4869291986690).
5483977325950 is a wasteful number, since it uses less digits than its factorization.
5483977325950 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131281 (or 131276 counting only the distinct ones).
The product of its (nonzero) digits is 285768000, while the sum is 67.
The spelling of 5483977325950 in words is "five trillion, four hundred eighty-three billion, nine hundred seventy-seven million, three hundred twenty-five thousand, nine hundred fifty".
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