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5490289853 is a prime number
BaseRepresentation
bin1010001110011111…
…10010110010111101
3112011121221121210122
411013033302302331
542221003233403
62304443544325
7253024456646
oct50717626275
915147847718
105490289853
112368142034
12109282b0a5
136965c4029
143a124a6cd
15222002838
hex1473f2cbd

5490289853 has 2 divisors, whose sum is σ = 5490289854. Its totient is φ = 5490289852.

The previous prime is 5490289801. The next prime is 5490289891. The reversal of 5490289853 is 3589820945.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4885031449 + 605258404 = 69893^2 + 24602^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5490289853 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5490289795 and 5490289804.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5490286853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2745144926 + 2745144927.

It is an arithmetic number, because the mean of its divisors is an integer number (2745144927).

Almost surely, 25490289853 is an apocalyptic number.

It is an amenable number.

5490289853 is a deficient number, since it is larger than the sum of its proper divisors (1).

5490289853 is an equidigital number, since it uses as much as digits as its factorization.

5490289853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3110400, while the sum is 53.

The square root of 5490289853 is about 74096.4901530430. The cubic root of 5490289853 is about 1764.1347617602.

The spelling of 5490289853 in words is "five billion, four hundred ninety million, two hundred eighty-nine thousand, eight hundred fifty-three".