Base | Representation |
---|---|
bin | 110011001100011010… |
… | …000110000011000101 |
3 | 12020212212212112100211 |
4 | 303030122012003011 |
5 | 1400034031001013 |
6 | 41130304235421 |
7 | 3654116535415 |
oct | 631432060305 |
9 | 166785775324 |
10 | 54969000133 |
11 | 21348627433 |
12 | a7a100bb71 |
13 | 52503664a8 |
14 | 2936642645 |
15 | 166ac2623d |
hex | ccc6860c5 |
54969000133 has 2 divisors, whose sum is σ = 54969000134. Its totient is φ = 54969000132.
The previous prime is 54969000109. The next prime is 54969000181. The reversal of 54969000133 is 33100096945.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 54764424324 + 204575809 = 234018^2 + 14303^2 .
It is a cyclic number.
It is not a de Polignac number, because 54969000133 - 25 = 54969000101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54969000193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27484500066 + 27484500067.
It is an arithmetic number, because the mean of its divisors is an integer number (27484500067).
Almost surely, 254969000133 is an apocalyptic number.
It is an amenable number.
54969000133 is a deficient number, since it is larger than the sum of its proper divisors (1).
54969000133 is an equidigital number, since it uses as much as digits as its factorization.
54969000133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 87480, while the sum is 40.
The spelling of 54969000133 in words is "fifty-four billion, nine hundred sixty-nine million, one hundred thirty-three", and thus it is an aban number.
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