Base | Representation |
---|---|
bin | 110011001100011010… |
… | …000110000011110101 |
3 | 12020212212212112102121 |
4 | 303030122012003311 |
5 | 1400034031001211 |
6 | 41130304235541 |
7 | 3654116535514 |
oct | 631432060365 |
9 | 166785775377 |
10 | 54969000181 |
11 | 21348627477 |
12 | a7a100bbb1 |
13 | 5250366514 |
14 | 293664267b |
15 | 166ac26271 |
hex | ccc6860f5 |
54969000181 has 2 divisors, whose sum is σ = 54969000182. Its totient is φ = 54969000180.
The previous prime is 54969000133. The next prime is 54969000193. The reversal of 54969000181 is 18100096945.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53835600625 + 1133399556 = 232025^2 + 33666^2 .
It is a cyclic number.
It is not a de Polignac number, because 54969000181 - 215 = 54968967413 is a prime.
It is a super-2 number, since 2×549690001812 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54969000101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27484500090 + 27484500091.
It is an arithmetic number, because the mean of its divisors is an integer number (27484500091).
Almost surely, 254969000181 is an apocalyptic number.
It is an amenable number.
54969000181 is a deficient number, since it is larger than the sum of its proper divisors (1).
54969000181 is an equidigital number, since it uses as much as digits as its factorization.
54969000181 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 43.
The spelling of 54969000181 in words is "fifty-four billion, nine hundred sixty-nine million, one hundred eighty-one", and thus it is an aban number.
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