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550011101119 is a prime number
BaseRepresentation
bin10000000000011110011…
…01110101111110111111
31221120200012220212201221
420000033031311332333
533002410320213434
61100401022414211
754510534136024
oct10001715657677
91846605825657
10550011101119
111a2292a22a27
128a719731367
133cb342a65bc
141c89920354b
15e49146c2b4
hex800f375fbf

550011101119 has 2 divisors, whose sum is σ = 550011101120. Its totient is φ = 550011101118.

The previous prime is 550011101093. The next prime is 550011101137. The reversal of 550011101119 is 911101110055.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 550011101119 - 225 = 549977546687 is a prime.

It is a super-2 number, since 2×5500111011192 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 550011101093 and 550011101102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (550011101719) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275005550559 + 275005550560.

It is an arithmetic number, because the mean of its divisors is an integer number (275005550560).

Almost surely, 2550011101119 is an apocalyptic number.

550011101119 is a deficient number, since it is larger than the sum of its proper divisors (1).

550011101119 is an equidigital number, since it uses as much as digits as its factorization.

550011101119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 225, while the sum is 25.

The spelling of 550011101119 in words is "five hundred fifty billion, eleven million, one hundred one thousand, one hundred nineteen".