Base | Representation |
---|---|
bin | 10000000000011110011… |
… | …01110101111110111111 |
3 | 1221120200012220212201221 |
4 | 20000033031311332333 |
5 | 33002410320213434 |
6 | 1100401022414211 |
7 | 54510534136024 |
oct | 10001715657677 |
9 | 1846605825657 |
10 | 550011101119 |
11 | 1a2292a22a27 |
12 | 8a719731367 |
13 | 3cb342a65bc |
14 | 1c89920354b |
15 | e49146c2b4 |
hex | 800f375fbf |
550011101119 has 2 divisors, whose sum is σ = 550011101120. Its totient is φ = 550011101118.
The previous prime is 550011101093. The next prime is 550011101137. The reversal of 550011101119 is 911101110055.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 550011101119 - 225 = 549977546687 is a prime.
It is a super-2 number, since 2×5500111011192 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 550011101093 and 550011101102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (550011101719) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275005550559 + 275005550560.
It is an arithmetic number, because the mean of its divisors is an integer number (275005550560).
Almost surely, 2550011101119 is an apocalyptic number.
550011101119 is a deficient number, since it is larger than the sum of its proper divisors (1).
550011101119 is an equidigital number, since it uses as much as digits as its factorization.
550011101119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 225, while the sum is 25.
The spelling of 550011101119 in words is "five hundred fifty billion, eleven million, one hundred one thousand, one hundred nineteen".
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