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550055549941 is a prime number
BaseRepresentation
bin10000000000100011101…
…11011001101111110101
31221120210022120010001121
420000101313121233311
533003003210044231
61100405251223541
754511614013312
oct10002167315765
91846708503047
10550055549941
111a2306021a97
128a7305a7bb1
133cb4056a091
141c8a1093d09
15e4952ec311
hex8011dd9bf5

550055549941 has 2 divisors, whose sum is σ = 550055549942. Its totient is φ = 550055549940.

The previous prime is 550055549933. The next prime is 550055549963. The reversal of 550055549941 is 149945550055.

It is a happy number.

550055549941 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 530719535025 + 19336014916 = 728505^2 + 139054^2 .

It is a cyclic number.

It is not a de Polignac number, because 550055549941 - 23 = 550055549933 is a prime.

It is a super-3 number, since 3×5500555499413 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (550055549971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275027774970 + 275027774971.

It is an arithmetic number, because the mean of its divisors is an integer number (275027774971).

Almost surely, 2550055549941 is an apocalyptic number.

It is an amenable number.

550055549941 is a deficient number, since it is larger than the sum of its proper divisors (1).

550055549941 is an equidigital number, since it uses as much as digits as its factorization.

550055549941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4050000, while the sum is 52.

The spelling of 550055549941 in words is "five hundred fifty billion, fifty-five million, five hundred forty-nine thousand, nine hundred forty-one".