Base | Representation |
---|---|
bin | 10000000000101010001… |
… | …11001111010011101111 |
3 | 1221120221010002010221200 |
4 | 20000111013033103233 |
5 | 33003111132030020 |
6 | 1100414515100543 |
7 | 54513145062405 |
oct | 10002507172357 |
9 | 1846833063850 |
10 | 550110033135 |
11 | 1a2333855023 |
12 | 8a7468a1753 |
13 | 3cb4b934c60 |
14 | 1c8a83d7475 |
15 | e499eb0590 |
hex | 80151cf4ef |
550110033135 has 96 divisors (see below), whose sum is σ = 1038145949568. Its totient is φ = 267853824000.
The previous prime is 550110033133. The next prime is 550110033149. The reversal of 550110033135 is 531330011055.
550110033135 is a `hidden beast` number, since 550 + 1 + 100 + 3 + 3 + 1 + 3 + 5 = 666.
It is not a de Polignac number, because 550110033135 - 21 = 550110033133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 550110033099 and 550110033108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (550110033133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 137491135 + ... + 137495135.
It is an arithmetic number, because the mean of its divisors is an integer number (10814020308).
Almost surely, 2550110033135 is an apocalyptic number.
550110033135 is a deficient number, since it is larger than the sum of its proper divisors (488035916433).
550110033135 is a wasteful number, since it uses less digits than its factorization.
550110033135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6545 (or 6542 counting only the distinct ones).
The product of its (nonzero) digits is 3375, while the sum is 27.
The spelling of 550110033135 in words is "five hundred fifty billion, one hundred ten million, thirty-three thousand, one hundred thirty-five".
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