Base | Representation |
---|---|
bin | 111110100010100101001100… |
… | …0000110110111011100100111 |
3 | 2200010210001111021222110121011 |
4 | 1331011022120012313130213 |
5 | 1034101002403101034304 |
6 | 5225553144352403051 |
7 | 223605114221661355 |
oct | 17505123006673447 |
9 | 2603701437873534 |
10 | 550110553143079 |
11 | 14a311636995605 |
12 | 5184713b246487 |
13 | 1a7c5283084856 |
14 | 99bb6c84b47d5 |
15 | 438e987eb9c04 |
hex | 1f452981b7727 |
550110553143079 has 2 divisors, whose sum is σ = 550110553143080. Its totient is φ = 550110553143078.
The previous prime is 550110553143049. The next prime is 550110553143113. The reversal of 550110553143079 is 970341355011055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 550110553143079 - 211 = 550110553141031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (550110553143049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275055276571539 + 275055276571540.
It is an arithmetic number, because the mean of its divisors is an integer number (275055276571540).
Almost surely, 2550110553143079 is an apocalyptic number.
550110553143079 is a deficient number, since it is larger than the sum of its proper divisors (1).
550110553143079 is an equidigital number, since it uses as much as digits as its factorization.
550110553143079 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1417500, while the sum is 49.
The spelling of 550110553143079 in words is "five hundred fifty trillion, one hundred ten billion, five hundred fifty-three million, one hundred forty-three thousand, seventy-nine".
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