Base | Representation |
---|---|
bin | 110011001110111010… |
… | …101110101000010101 |
3 | 12020222211002220102012 |
4 | 303032322232220111 |
5 | 1400130321000042 |
6 | 41134410554005 |
7 | 3655140500066 |
oct | 631672565025 |
9 | 166884086365 |
10 | 55011109397 |
11 | 2136a378782 |
12 | a7b3138905 |
13 | 5258cbb10a |
14 | 293c08456d |
15 | 166e792e82 |
hex | cceeaea15 |
55011109397 has 2 divisors, whose sum is σ = 55011109398. Its totient is φ = 55011109396.
The previous prime is 55011109339. The next prime is 55011109399. The reversal of 55011109397 is 79390111055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44940184081 + 10070925316 = 211991^2 + 100354^2 .
It is a cyclic number.
It is not a de Polignac number, because 55011109397 - 28 = 55011109141 is a prime.
Together with 55011109399, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55011109399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27505554698 + 27505554699.
It is an arithmetic number, because the mean of its divisors is an integer number (27505554699).
Almost surely, 255011109397 is an apocalyptic number.
It is an amenable number.
55011109397 is a deficient number, since it is larger than the sum of its proper divisors (1).
55011109397 is an equidigital number, since it uses as much as digits as its factorization.
55011109397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42525, while the sum is 41.
The spelling of 55011109397 in words is "fifty-five billion, eleven million, one hundred nine thousand, three hundred ninety-seven".
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