Base | Representation |
---|---|
bin | 11001000001000010101110… |
… | …01001110101111011110111 |
3 | 21012210001001021122022220220 |
4 | 30200201113021311323313 |
5 | 24202301323222401200 |
6 | 312555520110425423 |
7 | 14405304600020253 |
oct | 1440412711657367 |
9 | 235701037568826 |
10 | 55011403325175 |
11 | 1658a22903a630 |
12 | 62056b3802273 |
13 | 249072614881b |
14 | d827cd64d263 |
15 | 655e8d53e4a0 |
hex | 320857275ef7 |
55011403325175 has 24 divisors (see below), whose sum is σ = 99220567453440. Its totient is φ = 26672195551200.
The previous prime is 55011403325173. The next prime is 55011403325183. The reversal of 55011403325175 is 57152330411055.
It is a happy number.
It is not a de Polignac number, because 55011403325175 - 21 = 55011403325173 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55011403325173) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 33340243615 + ... + 33340245264.
It is an arithmetic number, because the mean of its divisors is an integer number (4134190310560).
Almost surely, 255011403325175 is an apocalyptic number.
55011403325175 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55011403325175 is a deficient number, since it is larger than the sum of its proper divisors (44209164128265).
55011403325175 is a wasteful number, since it uses less digits than its factorization.
55011403325175 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66680488903 (or 66680488898 counting only the distinct ones).
The product of its (nonzero) digits is 315000, while the sum is 42.
The spelling of 55011403325175 in words is "fifty-five trillion, eleven billion, four hundred three million, three hundred twenty-five thousand, one hundred seventy-five".
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