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5501400111373 is a prime number
BaseRepresentation
bin101000000001110010011…
…1111111101100100001101
3201110221002000212212101111
41100003210333331210031
51210113331412030443
615411150333012021
71105314552250045
oct120034477754415
921427060785344
105501400111373
111831148a3a3a1
1274a25b924011
1330ba1a2cc3ba
141503aa90a725
159818621c69d
hex500e4ffd90d

5501400111373 has 2 divisors, whose sum is σ = 5501400111374. Its totient is φ = 5501400111372.

The previous prime is 5501400111371. The next prime is 5501400111461. The reversal of 5501400111373 is 3731110041055.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5044502524009 + 456897587364 = 2245997^2 + 675942^2 .

It is a cyclic number.

It is not a de Polignac number, because 5501400111373 - 21 = 5501400111371 is a prime.

Together with 5501400111371, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5501400111371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750700055686 + 2750700055687.

It is an arithmetic number, because the mean of its divisors is an integer number (2750700055687).

Almost surely, 25501400111373 is an apocalyptic number.

It is an amenable number.

5501400111373 is a deficient number, since it is larger than the sum of its proper divisors (1).

5501400111373 is an equidigital number, since it uses as much as digits as its factorization.

5501400111373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6300, while the sum is 31.

The spelling of 5501400111373 in words is "five trillion, five hundred one billion, four hundred million, one hundred eleven thousand, three hundred seventy-three".