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550215130117 is a prime number
BaseRepresentation
bin10000000000110110110…
…00001001110000000101
31221121012102211121220111
420000123120021300011
533003320033130432
61100433151433021
754515562303532
oct10003330116005
91847172747814
10550215130117
111a2388107a34
128a775b25771
133cb67641713
141c8b8353d89
15e4a4320347
hex801b609c05

550215130117 has 2 divisors, whose sum is σ = 550215130118. Its totient is φ = 550215130116.

The previous prime is 550215130111. The next prime is 550215130123. The reversal of 550215130117 is 711031512055.

It is a balanced prime because it is at equal distance from previous prime (550215130111) and next prime (550215130123).

It can be written as a sum of positive squares in only one way, i.e., 403410441316 + 146804688801 = 635146^2 + 383151^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-550215130117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (550215130111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275107565058 + 275107565059.

It is an arithmetic number, because the mean of its divisors is an integer number (275107565059).

Almost surely, 2550215130117 is an apocalyptic number.

It is an amenable number.

550215130117 is a deficient number, since it is larger than the sum of its proper divisors (1).

550215130117 is an equidigital number, since it uses as much as digits as its factorization.

550215130117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5250, while the sum is 31.

The spelling of 550215130117 in words is "five hundred fifty billion, two hundred fifteen million, one hundred thirty thousand, one hundred seventeen".