Base | Representation |
---|---|
bin | 111110100011011110101110… |
… | …1010110011110101111110111 |
3 | 2200011012212102222111221100120 |
4 | 1331012331131112132233313 |
5 | 1034110013440041311210 |
6 | 5230130022113543023 |
7 | 223620050320052544 |
oct | 17506753526365767 |
9 | 2604185388457316 |
10 | 550234121432055 |
11 | 14a359a86a79a85 |
12 | 51867085b74a73 |
13 | 1a803b165c82c8 |
14 | 99c368b6b3bcb |
15 | 4392cbb36b270 |
hex | 1f46f5d59ebf7 |
550234121432055 has 64 divisors (see below), whose sum is σ = 954127999047168. Its totient is φ = 269691195432960.
The previous prime is 550234121432041. The next prime is 550234121432059.
550234121432055 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 550234121432055 - 213 = 550234121423863 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 550234121431998 and 550234121432016.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (550234121432059) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 28674175 + ... + 43848335.
It is an arithmetic number, because the mean of its divisors is an integer number (14908249985112).
Almost surely, 2550234121432055 is an apocalyptic number.
550234121432055 is a deficient number, since it is larger than the sum of its proper divisors (403893877615113).
550234121432055 is a wasteful number, since it uses less digits than its factorization.
550234121432055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15177536.
The product of its (nonzero) digits is 720000, while the sum is 42.
The spelling of 550234121432055 in words is "five hundred fifty trillion, two hundred thirty-four billion, one hundred twenty-one million, four hundred thirty-two thousand, fifty-five".
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