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550234153104509 is a prime number
BaseRepresentation
bin111110100011011110101111…
…1001111010011010001111101
32200011012212112012010001210102
41331012331133033103101331
51034110014021143321014
65230130025204450445
7223620051153215216
oct17506753717232175
92604185465101712
10550234153104509
1114a359aa2941a65
12518670946a9a25
131a803b200375c3
1499c369199a40d
154392cbe0258de
hex1f46f5f3d347d

550234153104509 has 2 divisors, whose sum is σ = 550234153104510. Its totient is φ = 550234153104508.

The previous prime is 550234153104481. The next prime is 550234153104539. The reversal of 550234153104509 is 905401351432055.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 446967461976025 + 103266691128484 = 21141605^2 + 10162022^2 .

It is a cyclic number.

It is not a de Polignac number, because 550234153104509 - 212 = 550234153100413 is a prime.

It is a super-2 number, since 2×5502341531045092 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (550234153104539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275117076552254 + 275117076552255.

It is an arithmetic number, because the mean of its divisors is an integer number (275117076552255).

Almost surely, 2550234153104509 is an apocalyptic number.

It is an amenable number.

550234153104509 is a deficient number, since it is larger than the sum of its proper divisors (1).

550234153104509 is an equidigital number, since it uses as much as digits as its factorization.

550234153104509 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620000, while the sum is 47.

The spelling of 550234153104509 in words is "five hundred fifty trillion, two hundred thirty-four billion, one hundred fifty-three million, one hundred four thousand, five hundred nine".