Base | Representation |
---|---|
bin | 11001000001110001010100… |
… | …11010010001111001001111 |
3 | 21012212102121220120012222012 |
4 | 30200320222122101321033 |
5 | 24203204043122304210 |
6 | 313015214453411435 |
7 | 14410151566130225 |
oct | 1440705232217117 |
9 | 235772556505865 |
10 | 55036422463055 |
11 | 165998a7758190 |
12 | 620a516639b7b |
13 | 2492bb2622c17 |
14 | d83ac4378b15 |
15 | 656954c42305 |
hex | 320e2a691e4f |
55036422463055 has 64 divisors (see below), whose sum is σ = 76126548556800. Its totient is φ = 37776436715520.
The previous prime is 55036422463039. The next prime is 55036422463151.
It is a happy number.
55036422463055 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 55036422463055 - 24 = 55036422463039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55036422462994 and 55036422463012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2188053359 + ... + 2188078511.
It is an arithmetic number, because the mean of its divisors is an integer number (1189477321200).
Almost surely, 255036422463055 is an apocalyptic number.
55036422463055 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55036422463055 is a deficient number, since it is larger than the sum of its proper divisors (21090126093745).
55036422463055 is a wasteful number, since it uses less digits than its factorization.
55036422463055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33024.
The product of its (nonzero) digits is 12960000, while the sum is 50.
It can be divided in two parts, 5503642 and 2463055, that added together give a palindrome (7966697).
The spelling of 55036422463055 in words is "fifty-five trillion, thirty-six billion, four hundred twenty-two million, four hundred sixty-three thousand, fifty-five".
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