Base | Representation |
---|---|
bin | 110011010000111001… |
… | …111001010001110101 |
3 | 12021002010211112200022 |
4 | 303100321321101311 |
5 | 1400212334222201 |
6 | 41142001254525 |
7 | 3656024031236 |
oct | 632071712165 |
9 | 167063745608 |
10 | 55044445301 |
11 | 2138717750a |
12 | a802334445 |
13 | 5262b905c1 |
14 | 294268108d |
15 | 167267a41b |
hex | cd0e79475 |
55044445301 has 2 divisors, whose sum is σ = 55044445302. Its totient is φ = 55044445300.
The previous prime is 55044445279. The next prime is 55044445303. The reversal of 55044445301 is 10354444055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51166892401 + 3877552900 = 226201^2 + 62270^2 .
It is a cyclic number.
It is not a de Polignac number, because 55044445301 - 26 = 55044445237 is a prime.
Together with 55044445303, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55044445303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27522222650 + 27522222651.
It is an arithmetic number, because the mean of its divisors is an integer number (27522222651).
Almost surely, 255044445301 is an apocalyptic number.
It is an amenable number.
55044445301 is a deficient number, since it is larger than the sum of its proper divisors (1).
55044445301 is an equidigital number, since it uses as much as digits as its factorization.
55044445301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96000, while the sum is 35.
Adding to 55044445301 its reverse (10354444055), we get a palindrome (65398889356).
The spelling of 55044445301 in words is "fifty-five billion, forty-four million, four hundred forty-five thousand, three hundred one".
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