Base | Representation |
---|---|
bin | 10000000001011010000… |
… | …10000100100001101111 |
3 | 1221121222002012012201211 |
4 | 20000231002010201233 |
5 | 33004421400101224 |
6 | 1100522412215251 |
7 | 54526120052326 |
oct | 10005502044157 |
9 | 1847862165654 |
10 | 550511331439 |
11 | 1a251a327413 |
12 | 8a83916a527 |
13 | 3cbb3b0c484 |
14 | 1c9058190bd |
15 | e4c032d894 |
hex | 802d08486f |
550511331439 has 2 divisors, whose sum is σ = 550511331440. Its totient is φ = 550511331438.
The previous prime is 550511331437. The next prime is 550511331451. The reversal of 550511331439 is 934133115055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 550511331439 - 21 = 550511331437 is a prime.
Together with 550511331437, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (550511331437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275255665719 + 275255665720.
It is an arithmetic number, because the mean of its divisors is an integer number (275255665720).
Almost surely, 2550511331439 is an apocalyptic number.
550511331439 is a deficient number, since it is larger than the sum of its proper divisors (1).
550511331439 is an equidigital number, since it uses as much as digits as its factorization.
550511331439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 121500, while the sum is 40.
The spelling of 550511331439 in words is "five hundred fifty billion, five hundred eleven million, three hundred thirty-one thousand, four hundred thirty-nine".
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