Base | Representation |
---|---|
bin | 11001000011101000101100… |
… | …11010110001000110100111 |
3 | 21020002120001101111110201112 |
4 | 30201310112122301012213 |
5 | 24210231321424243012 |
6 | 313104454153215235 |
7 | 14414611020335561 |
oct | 1441642632610647 |
9 | 236076041443645 |
10 | 55100511556007 |
11 | 16613aa5340305 |
12 | 621aa21a0151b |
13 | 2498c57296928 |
14 | d86c43d34331 |
15 | 658456468122 |
hex | 321d166b11a7 |
55100511556007 has 2 divisors, whose sum is σ = 55100511556008. Its totient is φ = 55100511556006.
The previous prime is 55100511555983. The next prime is 55100511556009. The reversal of 55100511556007 is 70065511500155.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55100511556007 - 220 = 55100510507431 is a prime.
Together with 55100511556009, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55100511556009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27550255778003 + 27550255778004.
It is an arithmetic number, because the mean of its divisors is an integer number (27550255778004).
Almost surely, 255100511556007 is an apocalyptic number.
55100511556007 is a deficient number, since it is larger than the sum of its proper divisors (1).
55100511556007 is an equidigital number, since it uses as much as digits as its factorization.
55100511556007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 131250, while the sum is 41.
The spelling of 55100511556007 in words is "fifty-five trillion, one hundred billion, five hundred eleven million, five hundred fifty-six thousand, seven".
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