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55104703 is a prime number
BaseRepresentation
bin1101001000110…
…1010010111111
310211200121102221
43102031102333
5103101322303
65245030211
71236245053
oct322152277
9124617387
1055104703
1129117a85
1216555367
13b554a44
147465c63
154c874bd
hex348d4bf

55104703 has 2 divisors, whose sum is σ = 55104704. Its totient is φ = 55104702.

The previous prime is 55104677. The next prime is 55104719. The reversal of 55104703 is 30740155.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 55104703 - 213 = 55096511 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55104773) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27552351 + 27552352.

It is an arithmetic number, because the mean of its divisors is an integer number (27552352).

Almost surely, 255104703 is an apocalyptic number.

55104703 is a deficient number, since it is larger than the sum of its proper divisors (1).

55104703 is an equidigital number, since it uses as much as digits as its factorization.

55104703 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2100, while the sum is 25.

The square root of 55104703 is about 7423.2542055355. The cubic root of 55104703 is about 380.5364146383.

Adding to 55104703 its reverse (30740155), we get a palindrome (85844858).

The spelling of 55104703 in words is "fifty-five million, one hundred four thousand, seven hundred three".