Base | Representation |
---|---|
bin | 1010010000111101… |
… | …10100001100110101 |
3 | 112020001221001121121 |
4 | 11020132310030311 |
5 | 42241304124411 |
6 | 2310503543541 |
7 | 253365524626 |
oct | 51036641465 |
9 | 15201831547 |
10 | 5511004981 |
11 | 2378900679 |
12 | 109975abb1 |
13 | 69a997ac1 |
14 | 3a3cbda4d |
15 | 223c45571 |
hex | 1487b4335 |
5511004981 has 2 divisors, whose sum is σ = 5511004982. Its totient is φ = 5511004980.
The previous prime is 5511004969. The next prime is 5511004991. The reversal of 5511004981 is 1894001155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5054499025 + 456505956 = 71095^2 + 21366^2 .
It is a cyclic number.
It is not a de Polignac number, because 5511004981 - 25 = 5511004949 is a prime.
It is a super-2 number, since 2×55110049812 = 60742351801213620722, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5511004931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2755502490 + 2755502491.
It is an arithmetic number, because the mean of its divisors is an integer number (2755502491).
Almost surely, 25511004981 is an apocalyptic number.
It is an amenable number.
5511004981 is a deficient number, since it is larger than the sum of its proper divisors (1).
5511004981 is an equidigital number, since it uses as much as digits as its factorization.
5511004981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 34.
The square root of 5511004981 is about 74236.1433602258. The cubic root of 5511004981 is about 1766.3506989493.
The spelling of 5511004981 in words is "five billion, five hundred eleven million, four thousand, nine hundred eighty-one".
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