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551100555041 is a prime number
BaseRepresentation
bin10000000010100000010…
…01110001111100100001
31221200111010220212120012
420001100021301330201
533012123220230131
61101101101254305
754546533266361
oct10012011617441
91850433825505
10551100555041
111a27a1994873
128a982564395
133cc78c03caa
141c95db989a1
15e506e1d52b
hex8050271f21

551100555041 has 2 divisors, whose sum is σ = 551100555042. Its totient is φ = 551100555040.

The previous prime is 551100554989. The next prime is 551100555043. The reversal of 551100555041 is 140555001155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 495234505441 + 55866049600 = 703729^2 + 236360^2 .

It is a cyclic number.

It is not a de Polignac number, because 551100555041 - 214 = 551100538657 is a prime.

It is a Sophie Germain prime.

Together with 551100555043, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 551100554989 and 551100555007.

It is not a weakly prime, because it can be changed into another prime (551100555043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275550277520 + 275550277521.

It is an arithmetic number, because the mean of its divisors is an integer number (275550277521).

Almost surely, 2551100555041 is an apocalyptic number.

It is an amenable number.

551100555041 is a deficient number, since it is larger than the sum of its proper divisors (1).

551100555041 is an equidigital number, since it uses as much as digits as its factorization.

551100555041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12500, while the sum is 32.

Adding to 551100555041 its reverse (140555001155), we get a palindrome (691655556196).

The spelling of 551100555041 in words is "five hundred fifty-one billion, one hundred million, five hundred fifty-five thousand, forty-one".