Base | Representation |
---|---|
bin | 110011010101000111… |
… | …001111000001001011 |
3 | 12021021001200200121021 |
4 | 303111013033001023 |
5 | 1400333423113313 |
6 | 41153002453311 |
7 | 3660542130061 |
oct | 632507170113 |
9 | 167231620537 |
10 | 55115051083 |
11 | 214130116a4 |
12 | a821b04237 |
13 | 52746b1a81 |
14 | 294bbc0031 |
15 | 167897578d |
hex | cd51cf04b |
55115051083 has 2 divisors, whose sum is σ = 55115051084. Its totient is φ = 55115051082.
The previous prime is 55115051011. The next prime is 55115051137. The reversal of 55115051083 is 38015051155.
It is a happy number.
55115051083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55115051083 is a prime.
It is not a weakly prime, because it can be changed into another prime (55115051003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27557525541 + 27557525542.
It is an arithmetic number, because the mean of its divisors is an integer number (27557525542).
Almost surely, 255115051083 is an apocalyptic number.
55115051083 is a deficient number, since it is larger than the sum of its proper divisors (1).
55115051083 is an equidigital number, since it uses as much as digits as its factorization.
55115051083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15000, while the sum is 34.
The spelling of 55115051083 in words is "fifty-five billion, one hundred fifteen million, fifty-one thousand, eighty-three".
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