Base | Representation |
---|---|
bin | 10000000010101101100… |
… | …01001000010000101101 |
3 | 1221200202212202011012012 |
4 | 20001112301020100231 |
5 | 33012340123031412 |
6 | 1101120104051005 |
7 | 54552351504332 |
oct | 10012661102055 |
9 | 1850685664165 |
10 | 551211533357 |
11 | 1a28495a4491 |
12 | 8a9b3763a65 |
13 | 3cc95bbc734 |
14 | 1c970806989 |
15 | e511a40c22 |
hex | 8056c4842d |
551211533357 has 2 divisors, whose sum is σ = 551211533358. Its totient is φ = 551211533356.
The previous prime is 551211533329. The next prime is 551211533359. The reversal of 551211533357 is 753335112155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 303475384996 + 247736148361 = 550886^2 + 497731^2 .
It is a cyclic number.
It is not a de Polignac number, because 551211533357 - 218 = 551211271213 is a prime.
Together with 551211533359, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (551211533359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275605766678 + 275605766679.
It is an arithmetic number, because the mean of its divisors is an integer number (275605766679).
Almost surely, 2551211533357 is an apocalyptic number.
It is an amenable number.
551211533357 is a deficient number, since it is larger than the sum of its proper divisors (1).
551211533357 is an equidigital number, since it uses as much as digits as its factorization.
551211533357 is an evil number, because the sum of its binary digits is even.
The product of its digits is 236250, while the sum is 41.
The spelling of 551211533357 in words is "five hundred fifty-one billion, two hundred eleven million, five hundred thirty-three thousand, three hundred fifty-seven".
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