Base | Representation |
---|---|
bin | 110011010101011111… |
… | …100000000001001101 |
3 | 12021021111122212101012 |
4 | 303111133200001031 |
5 | 1400342040142143 |
6 | 41153351055005 |
7 | 3660650162402 |
oct | 632537400115 |
9 | 167244585335 |
10 | 55121412173 |
11 | 214166668a3 |
12 | a824071465 |
13 | 5275acb229 |
14 | 294c9982a9 |
15 | 16792d0418 |
hex | cd57e004d |
55121412173 has 2 divisors, whose sum is σ = 55121412174. Its totient is φ = 55121412172.
The previous prime is 55121412113. The next prime is 55121412191. The reversal of 55121412173 is 37121412155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32928457444 + 22192954729 = 181462^2 + 148973^2 .
It is a cyclic number.
It is not a de Polignac number, because 55121412173 - 212 = 55121408077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55121412113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27560706086 + 27560706087.
It is an arithmetic number, because the mean of its divisors is an integer number (27560706087).
Almost surely, 255121412173 is an apocalyptic number.
It is an amenable number.
55121412173 is a deficient number, since it is larger than the sum of its proper divisors (1).
55121412173 is an equidigital number, since it uses as much as digits as its factorization.
55121412173 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8400, while the sum is 32.
The spelling of 55121412173 in words is "fifty-five billion, one hundred twenty-one million, four hundred twelve thousand, one hundred seventy-three".
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