Base | Representation |
---|---|
bin | 101000000110110010101… |
… | …0110000010100101101101 |
3 | 201111221210202010021110102 |
4 | 1100031211112002211231 |
5 | 1210302332142123412 |
6 | 15420124345120445 |
7 | 1106145023063225 |
oct | 120154526024555 |
9 | 21457722107412 |
10 | 5512143317357 |
11 | 1835761224026 |
12 | 750359789125 |
13 | 30ca3cc75b11 |
14 | 150b09653085 |
15 | 985b44848c2 |
hex | 5036558296d |
5512143317357 has 2 divisors, whose sum is σ = 5512143317358. Its totient is φ = 5512143317356.
The previous prime is 5512143317203. The next prime is 5512143317377. The reversal of 5512143317357 is 7537133412155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5320744942276 + 191398375081 = 2306674^2 + 437491^2 .
It is a cyclic number.
It is not a de Polignac number, because 5512143317357 - 210 = 5512143316333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5512143317377) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2756071658678 + 2756071658679.
It is an arithmetic number, because the mean of its divisors is an integer number (2756071658679).
Almost surely, 25512143317357 is an apocalyptic number.
It is an amenable number.
5512143317357 is a deficient number, since it is larger than the sum of its proper divisors (1).
5512143317357 is an equidigital number, since it uses as much as digits as its factorization.
5512143317357 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1323000, while the sum is 47.
The spelling of 5512143317357 in words is "five trillion, five hundred twelve billion, one hundred forty-three million, three hundred seventeen thousand, three hundred fifty-seven".
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