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551322320441 is a prime number
BaseRepresentation
bin10000000010111010101…
…11101111111000111001
31221201001121012201111112
420001131113233320321
533013102003223231
61101135102410105
754555165254624
oct10013527577071
91851047181445
10551322320441
111a28a6093462
128aa24890935
133ccb2b3c119
141c981404dbb
15e51b62692b
hex805d5efe39

551322320441 has 2 divisors, whose sum is σ = 551322320442. Its totient is φ = 551322320440.

The previous prime is 551322320347. The next prime is 551322320443. The reversal of 551322320441 is 144023223155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 396180866041 + 155141454400 = 629429^2 + 393880^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-551322320441 is a prime.

Together with 551322320443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 551322320398 and 551322320407.

It is not a weakly prime, because it can be changed into another prime (551322320443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275661160220 + 275661160221.

It is an arithmetic number, because the mean of its divisors is an integer number (275661160221).

Almost surely, 2551322320441 is an apocalyptic number.

It is an amenable number.

551322320441 is a deficient number, since it is larger than the sum of its proper divisors (1).

551322320441 is an equidigital number, since it uses as much as digits as its factorization.

551322320441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 551322320441 its reverse (144023223155), we get a palindrome (695345543596).

The spelling of 551322320441 in words is "five hundred fifty-one billion, three hundred twenty-two million, three hundred twenty thousand, four hundred forty-one".