Base | Representation |
---|---|
bin | 10000000010111011110… |
… | …01011010000101101001 |
3 | 1221201002012211000012112 |
4 | 20001131321122011221 |
5 | 33013111233102131 |
6 | 1101140015452105 |
7 | 54555333254456 |
oct | 10013571320551 |
9 | 1851065730175 |
10 | 551331144041 |
11 | 1a290006a797 |
12 | 8aa27827035 |
13 | 3ccb490b3a2 |
14 | 1c98266082d |
15 | e51c2bb02b |
hex | 805de5a169 |
551331144041 has 2 divisors, whose sum is σ = 551331144042. Its totient is φ = 551331144040.
The previous prime is 551331143983. The next prime is 551331144071. The reversal of 551331144041 is 140441133155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 451891828441 + 99439315600 = 672229^2 + 315340^2 .
It is a cyclic number.
It is not a de Polignac number, because 551331144041 - 214 = 551331127657 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 551331143989 and 551331144007.
It is not a weakly prime, because it can be changed into another prime (551331144071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275665572020 + 275665572021.
It is an arithmetic number, because the mean of its divisors is an integer number (275665572021).
Almost surely, 2551331144041 is an apocalyptic number.
It is an amenable number.
551331144041 is a deficient number, since it is larger than the sum of its proper divisors (1).
551331144041 is an equidigital number, since it uses as much as digits as its factorization.
551331144041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 551331144041 its reverse (140441133155), we get a palindrome (691772277196).
The spelling of 551331144041 in words is "five hundred fifty-one billion, three hundred thirty-one million, one hundred forty-four thousand, forty-one".
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