Base | Representation |
---|---|
bin | 10000000010111011110… |
… | …01011010000110000111 |
3 | 1221201002012211000020122 |
4 | 20001131321122012013 |
5 | 33013111233102241 |
6 | 1101140015452155 |
7 | 54555333254531 |
oct | 10013571320607 |
9 | 1851065730218 |
10 | 551331144071 |
11 | 1a290006a814 |
12 | 8aa2782705b |
13 | 3ccb490b3c6 |
14 | 1c982660851 |
15 | e51c2bb04b |
hex | 805de5a187 |
551331144071 has 2 divisors, whose sum is σ = 551331144072. Its totient is φ = 551331144070.
The previous prime is 551331144041. The next prime is 551331144131. The reversal of 551331144071 is 170441133155.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-551331144071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (551331144041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275665572035 + 275665572036.
It is an arithmetic number, because the mean of its divisors is an integer number (275665572036).
Almost surely, 2551331144071 is an apocalyptic number.
551331144071 is a deficient number, since it is larger than the sum of its proper divisors (1).
551331144071 is an equidigital number, since it uses as much as digits as its factorization.
551331144071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 35.
The spelling of 551331144071 in words is "five hundred fifty-one billion, three hundred thirty-one million, one hundred forty-four thousand, seventy-one".
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