Base | Representation |
---|---|
bin | 10000000011000100000… |
… | …00011101010001110101 |
3 | 1221201021000120101100021 |
4 | 20001202000131101311 |
5 | 33013231411212411 |
6 | 1101150521445141 |
7 | 54560131345222 |
oct | 10014200352165 |
9 | 1851230511307 |
10 | 551400100981 |
11 | 1a2935a890a4 |
12 | 8aa469407b1 |
13 | 3ccc5ca3202 |
14 | 1c98b890949 |
15 | e52338ca71 |
hex | 806201d475 |
551400100981 has 2 divisors, whose sum is σ = 551400100982. Its totient is φ = 551400100980.
The previous prime is 551400100973. The next prime is 551400101099. The reversal of 551400100981 is 189001004155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 546727148100 + 4672952881 = 739410^2 + 68359^2 .
It is a cyclic number.
It is not a de Polignac number, because 551400100981 - 23 = 551400100973 is a prime.
It is a super-2 number, since 2×5514001009812 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (551400107981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275700050490 + 275700050491.
It is an arithmetic number, because the mean of its divisors is an integer number (275700050491).
Almost surely, 2551400100981 is an apocalyptic number.
It is an amenable number.
551400100981 is a deficient number, since it is larger than the sum of its proper divisors (1).
551400100981 is an equidigital number, since it uses as much as digits as its factorization.
551400100981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 34.
The spelling of 551400100981 in words is "five hundred fifty-one billion, four hundred million, one hundred thousand, nine hundred eighty-one".
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