Base | Representation |
---|---|
bin | 11001000100111000010100… |
… | …00001100110010000111111 |
3 | 21020020122101010122020221011 |
4 | 30202130022001212100333 |
5 | 24211431340321220013 |
6 | 313140243313220051 |
7 | 14420653136242066 |
oct | 1442341201462077 |
9 | 236218333566834 |
10 | 55143253304383 |
11 | 166301389aa4a2 |
12 | 622716bb61627 |
13 | 249cca938c1ba |
14 | d88d3a6c11dd |
15 | 6596089cec3d |
hex | 32270a06643f |
55143253304383 has 2 divisors, whose sum is σ = 55143253304384. Its totient is φ = 55143253304382.
The previous prime is 55143253304329. The next prime is 55143253304437. The reversal of 55143253304383 is 38340335234155.
It is a balanced prime because it is at equal distance from previous prime (55143253304329) and next prime (55143253304437).
It is a cyclic number.
It is not a de Polignac number, because 55143253304383 - 233 = 55134663369791 is a prime.
It is a super-3 number, since 3×551432533043833 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55143253304983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27571626652191 + 27571626652192.
It is an arithmetic number, because the mean of its divisors is an integer number (27571626652192).
Almost surely, 255143253304383 is an apocalyptic number.
55143253304383 is a deficient number, since it is larger than the sum of its proper divisors (1).
55143253304383 is an equidigital number, since it uses as much as digits as its factorization.
55143253304383 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776000, while the sum is 49.
The spelling of 55143253304383 in words is "fifty-five trillion, one hundred forty-three billion, two hundred fifty-three million, three hundred four thousand, three hundred eighty-three".
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