Base | Representation |
---|---|
bin | 100000110111100… |
… | …101001011101011 |
3 | 1102102122010000121 |
4 | 200313211023223 |
5 | 2112132104011 |
6 | 130415144111 |
7 | 16444113043 |
oct | 4067451353 |
9 | 1372563017 |
10 | 551441131 |
11 | 26330197a |
12 | 134815037 |
13 | 8a326437 |
14 | 53346723 |
15 | 33629e71 |
hex | 20de52eb |
551441131 has 2 divisors, whose sum is σ = 551441132. Its totient is φ = 551441130.
The previous prime is 551441129. The next prime is 551441141. The reversal of 551441131 is 131144155.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 551441131 - 21 = 551441129 is a prime.
It is a super-2 number, since 2×5514411312 = 608174641917118322, which contains 22 as substring.
Together with 551441129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 551441096 and 551441105.
It is not a weakly prime, because it can be changed into another prime (551441101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275720565 + 275720566.
It is an arithmetic number, because the mean of its divisors is an integer number (275720566).
Almost surely, 2551441131 is an apocalyptic number.
551441131 is a deficient number, since it is larger than the sum of its proper divisors (1).
551441131 is an equidigital number, since it uses as much as digits as its factorization.
551441131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1200, while the sum is 25.
The square root of 551441131 is about 23482.7837148835. The cubic root of 551441131 is about 820.0362521153.
Adding to 551441131 its reverse (131144155), we get a palindrome (682585286).
The spelling of 551441131 in words is "five hundred fifty-one million, four hundred forty-one thousand, one hundred thirty-one".
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