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551441131 is a prime number
BaseRepresentation
bin100000110111100…
…101001011101011
31102102122010000121
4200313211023223
52112132104011
6130415144111
716444113043
oct4067451353
91372563017
10551441131
1126330197a
12134815037
138a326437
1453346723
1533629e71
hex20de52eb

551441131 has 2 divisors, whose sum is σ = 551441132. Its totient is φ = 551441130.

The previous prime is 551441129. The next prime is 551441141. The reversal of 551441131 is 131144155.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 551441131 - 21 = 551441129 is a prime.

It is a super-2 number, since 2×5514411312 = 608174641917118322, which contains 22 as substring.

Together with 551441129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 551441096 and 551441105.

It is not a weakly prime, because it can be changed into another prime (551441101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275720565 + 275720566.

It is an arithmetic number, because the mean of its divisors is an integer number (275720566).

Almost surely, 2551441131 is an apocalyptic number.

551441131 is a deficient number, since it is larger than the sum of its proper divisors (1).

551441131 is an equidigital number, since it uses as much as digits as its factorization.

551441131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1200, while the sum is 25.

The square root of 551441131 is about 23482.7837148835. The cubic root of 551441131 is about 820.0362521153.

Adding to 551441131 its reverse (131144155), we get a palindrome (682585286).

The spelling of 551441131 in words is "five hundred fifty-one million, four hundred forty-one thousand, one hundred thirty-one".