Base | Representation |
---|---|
bin | 10000000011001100101… |
… | …10100101010100110101 |
3 | 1221201110002202112200022 |
4 | 20001212112211110311 |
5 | 33013404042304343 |
6 | 1101202044254525 |
7 | 54562005145664 |
oct | 10014626452465 |
9 | 1851402675608 |
10 | 551473009973 |
11 | 1a2973156766 |
12 | 8aa67241445 |
13 | 4000811cb22 |
14 | 1c99742cddb |
15 | e529990568 |
hex | 80665a5535 |
551473009973 has 2 divisors, whose sum is σ = 551473009974. Its totient is φ = 551473009972.
The previous prime is 551473009963. The next prime is 551473010021. The reversal of 551473009973 is 379900374155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 401628922564 + 149844087409 = 633742^2 + 387097^2 .
It is a cyclic number.
It is not a de Polignac number, because 551473009973 - 26 = 551473009909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (551473009933) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275736504986 + 275736504987.
It is an arithmetic number, because the mean of its divisors is an integer number (275736504987).
Almost surely, 2551473009973 is an apocalyptic number.
It is an amenable number.
551473009973 is a deficient number, since it is larger than the sum of its proper divisors (1).
551473009973 is an equidigital number, since it uses as much as digits as its factorization.
551473009973 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3572100, while the sum is 53.
The spelling of 551473009973 in words is "five hundred fifty-one billion, four hundred seventy-three million, nine thousand, nine hundred seventy-three".
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