Base | Representation |
---|---|
bin | 11001000101000001001110… |
… | …11100110011111001111101 |
3 | 21020021002201212022101111222 |
4 | 30202200213130303321331 |
5 | 24212021142214212301 |
6 | 313142354414323125 |
7 | 14421212614100426 |
oct | 1442404734637175 |
9 | 236232655271458 |
10 | 55148041944701 |
11 | 16632175a75882 |
12 | 62280877b94a5 |
13 | 24a05904b7094 |
14 | d8927268464d |
15 | 6597d90d631b |
hex | 322827733e7d |
55148041944701 has 2 divisors, whose sum is σ = 55148041944702. Its totient is φ = 55148041944700.
The previous prime is 55148041944679. The next prime is 55148041944719. The reversal of 55148041944701 is 10744914084155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54557797005625 + 590244939076 = 7386325^2 + 768274^2 .
It is a cyclic number.
It is not a de Polignac number, because 55148041944701 - 26 = 55148041944637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55148041944731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27574020972350 + 27574020972351.
It is an arithmetic number, because the mean of its divisors is an integer number (27574020972351).
Almost surely, 255148041944701 is an apocalyptic number.
It is an amenable number.
55148041944701 is a deficient number, since it is larger than the sum of its proper divisors (1).
55148041944701 is an equidigital number, since it uses as much as digits as its factorization.
55148041944701 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3225600, while the sum is 53.
The spelling of 55148041944701 in words is "fifty-five trillion, one hundred forty-eight billion, forty-one million, nine hundred forty-four thousand, seven hundred one".
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