Base | Representation |
---|---|
bin | 10000000011101001001… |
… | …01001010001101100111 |
3 | 1221202001201220212102221 |
4 | 20001310211022031213 |
5 | 33014401144241403 |
6 | 1101241452413211 |
7 | 54600634114366 |
oct | 10016445121547 |
9 | 1852051825387 |
10 | 551711712103 |
11 | 1a2a85973152 |
12 | 8ab13177207 |
13 | 40045707ca6 |
14 | 1c9bb0077dd |
15 | e5408e1dbd |
hex | 807494a367 |
551711712103 has 2 divisors, whose sum is σ = 551711712104. Its totient is φ = 551711712102.
The previous prime is 551711712077. The next prime is 551711712107. The reversal of 551711712103 is 301217117155.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-551711712103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (551711712107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275855856051 + 275855856052.
It is an arithmetic number, because the mean of its divisors is an integer number (275855856052).
Almost surely, 2551711712103 is an apocalyptic number.
551711712103 is a deficient number, since it is larger than the sum of its proper divisors (1).
551711712103 is an equidigital number, since it uses as much as digits as its factorization.
551711712103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7350, while the sum is 34.
Adding to 551711712103 its reverse (301217117155), we get a palindrome (852928829258).
The spelling of 551711712103 in words is "five hundred fifty-one billion, seven hundred eleven million, seven hundred twelve thousand, one hundred three".
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