Base | Representation |
---|---|
bin | 11001000101101101010100… |
… | …01111100011001011100111 |
3 | 21020100100211102001002011222 |
4 | 30202312222033203023213 |
5 | 24212413131021320403 |
6 | 313201311215050555 |
7 | 14423011301546624 |
oct | 1442665217431347 |
9 | 236310742032158 |
10 | 55171711120103 |
11 | 16641211670666 |
12 | 6230792510a5b |
13 | 24a28930b2206 |
14 | d8a479da534b |
15 | 65a22202a338 |
hex | 322daa3e32e7 |
55171711120103 has 2 divisors, whose sum is σ = 55171711120104. Its totient is φ = 55171711120102.
The previous prime is 55171711120081. The next prime is 55171711120151. The reversal of 55171711120103 is 30102111717155.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55171711120103 - 212 = 55171711116007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55171711120153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27585855560051 + 27585855560052.
It is an arithmetic number, because the mean of its divisors is an integer number (27585855560052).
Almost surely, 255171711120103 is an apocalyptic number.
55171711120103 is a deficient number, since it is larger than the sum of its proper divisors (1).
55171711120103 is an equidigital number, since it uses as much as digits as its factorization.
55171711120103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7350, while the sum is 35.
Adding to 55171711120103 its reverse (30102111717155), we get a palindrome (85273822837258).
The spelling of 55171711120103 in words is "fifty-five trillion, one hundred seventy-one billion, seven hundred eleven million, one hundred twenty thousand, one hundred three".
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