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552081437 is a prime number
BaseRepresentation
bin100000111010000…
…001100000011101
31102110211122100122
4200322001200131
52112313101222
6130441004325
716452420605
oct4072014035
91373748318
10552081437
112636a9a56
12134a836a5
138a4bba0b
1453471c05
1533704a42
hex20e8181d

552081437 has 2 divisors, whose sum is σ = 552081438. Its totient is φ = 552081436.

The previous prime is 552081401. The next prime is 552081457. The reversal of 552081437 is 734180255.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 546671161 + 5410276 = 23381^2 + 2326^2 .

It is a cyclic number.

It is not a de Polignac number, because 552081437 - 222 = 547887133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 552081397 and 552081406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (552081457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276040718 + 276040719.

It is an arithmetic number, because the mean of its divisors is an integer number (276040719).

Almost surely, 2552081437 is an apocalyptic number.

It is an amenable number.

552081437 is a deficient number, since it is larger than the sum of its proper divisors (1).

552081437 is an equidigital number, since it uses as much as digits as its factorization.

552081437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 33600, while the sum is 35.

The square root of 552081437 is about 23496.4132794774. The cubic root of 552081437 is about 820.3535244429.

The spelling of 552081437 in words is "five hundred fifty-two million, eighty-one thousand, four hundred thirty-seven".