Base | Representation |
---|---|
bin | 111110110010001011010011… |
… | …0010110000000000000101111 |
3 | 2200102100222001110000201010202 |
4 | 1331210112212112000000233 |
5 | 1034341112123023001142 |
6 | 5234313550515224115 |
7 | 224216014315240523 |
oct | 17544264626000057 |
9 | 2612328043021122 |
10 | 552253980672047 |
11 | 14aa686639487a5 |
12 | 51b326308a803b |
13 | 1a91c433322054 |
14 | 9a53341887d83 |
15 | 43ca5d7a5d032 |
hex | 1f645a658002f |
552253980672047 has 2 divisors, whose sum is σ = 552253980672048. Its totient is φ = 552253980672046.
The previous prime is 552253980672029. The next prime is 552253980672101. The reversal of 552253980672047 is 740276089352255.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 552253980672047 - 222 = 552253976477743 is a prime.
It is a super-2 number, since 2×5522539806720472 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (552253980672007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276126990336023 + 276126990336024.
It is an arithmetic number, because the mean of its divisors is an integer number (276126990336024).
Almost surely, 2552253980672047 is an apocalyptic number.
552253980672047 is a deficient number, since it is larger than the sum of its proper divisors (1).
552253980672047 is an equidigital number, since it uses as much as digits as its factorization.
552253980672047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 254016000, while the sum is 65.
The spelling of 552253980672047 in words is "five hundred fifty-two trillion, two hundred fifty-three billion, nine hundred eighty million, six hundred seventy-two thousand, forty-seven".
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