Base | Representation |
---|---|
bin | 10000000101001001110… |
… | …00111110001001011011 |
3 | 1221211011020000112012002 |
4 | 20002210320332021123 |
5 | 33023031141240211 |
6 | 1101454124311215 |
7 | 54630005211554 |
oct | 10024470761133 |
9 | 1854136015162 |
10 | 552522211931 |
11 | 1a3361425718 |
12 | 8b0ba6a250b |
13 | 401445c60a1 |
14 | 1ca5690732b |
15 | e58bb4003b |
hex | 80a4e3e25b |
552522211931 has 2 divisors, whose sum is σ = 552522211932. Its totient is φ = 552522211930.
The previous prime is 552522211907. The next prime is 552522211933. The reversal of 552522211931 is 139112225255.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-552522211931 is a prime.
It is a super-2 number, since 2×5525222119312 (a number of 24 digits) contains 22 as substring.
Together with 552522211933, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (552522211933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276261105965 + 276261105966.
It is an arithmetic number, because the mean of its divisors is an integer number (276261105966).
Almost surely, 2552522211931 is an apocalyptic number.
552522211931 is a deficient number, since it is larger than the sum of its proper divisors (1).
552522211931 is an equidigital number, since it uses as much as digits as its factorization.
552522211931 is an evil number, because the sum of its binary digits is even.
The product of its digits is 54000, while the sum is 38.
The spelling of 552522211931 in words is "five hundred fifty-two billion, five hundred twenty-two million, two hundred eleven thousand, nine hundred thirty-one".
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