Base | Representation |
---|---|
bin | 110011100000110011… |
… | …001000111111000101 |
3 | 12021202201121111222210 |
4 | 303200303020333011 |
5 | 1401234121010320 |
6 | 41224245014033 |
7 | 3665442451500 |
oct | 634063107705 |
9 | 167681544883 |
10 | 55311110085 |
11 | 21503752730 |
12 | a8776b4319 |
13 | 52a61b930a |
14 | 2969c58137 |
15 | 168aca20e0 |
hex | ce0cc8fc5 |
55311110085 has 96 divisors (see below), whose sum is σ = 112935513600. Its totient is φ = 22857421440.
The previous prime is 55311110081. The next prime is 55311110117. The reversal of 55311110085 is 58001111355.
55311110085 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 55311110085 - 22 = 55311110081 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55311110081) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1428106 + ... + 1466324.
It is an arithmetic number, because the mean of its divisors is an integer number (1176411600).
Almost surely, 255311110085 is an apocalyptic number.
55311110085 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
55311110085 is an abundant number, since it is smaller than the sum of its proper divisors (57624403515).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
55311110085 is a wasteful number, since it uses less digits than its factorization.
55311110085 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38431 (or 38424 counting only the distinct ones).
The product of its (nonzero) digits is 3000, while the sum is 30.
The spelling of 55311110085 in words is "fifty-five billion, three hundred eleven million, one hundred ten thousand, eighty-five".
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