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553113132493 is a prime number
BaseRepresentation
bin10000000110010000001…
…11001001110111001101
31221212200101221101210211
420003020013021313031
533030233430214433
61102032514002421
754650442024205
oct10031007116715
91855611841724
10553113132493
111a3634a42019
128b244576411
1340209b6311c
141cab11a9405
15e5c39678cd
hex80c81c9dcd

553113132493 has 2 divisors, whose sum is σ = 553113132494. Its totient is φ = 553113132492.

The previous prime is 553113132479. The next prime is 553113132521. The reversal of 553113132493 is 394231311355.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 449646690249 + 103466442244 = 670557^2 + 321662^2 .

It is a cyclic number.

It is not a de Polignac number, because 553113132493 - 221 = 553111035341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (553113132893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276556566246 + 276556566247.

It is an arithmetic number, because the mean of its divisors is an integer number (276556566247).

Almost surely, 2553113132493 is an apocalyptic number.

It is an amenable number.

553113132493 is a deficient number, since it is larger than the sum of its proper divisors (1).

553113132493 is an equidigital number, since it uses as much as digits as its factorization.

553113132493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 145800, while the sum is 40.

The spelling of 553113132493 in words is "five hundred fifty-three billion, one hundred thirteen million, one hundred thirty-two thousand, four hundred ninety-three".