Base | Representation |
---|---|
bin | 101000001111111111100… |
… | …1011000011111111100010 |
3 | 201120211210220022221222020 |
4 | 1100133333023003333202 |
5 | 1211113314410444340 |
6 | 15433153245122310 |
7 | 1110444511106625 |
oct | 120377713037742 |
9 | 21524726287866 |
10 | 5531903999970 |
11 | 1843081656387 |
12 | 754153559396 |
13 | 31186bbab51a |
14 | 151a61c3ddbc |
15 | 98d6e1cb9d0 |
hex | 507ff2c3fe2 |
5531903999970 has 32 divisors (see below), whose sum is σ = 13276880793792. Its totient is φ = 1475139822912.
The previous prime is 5531903999953. The next prime is 5531903999971. The reversal of 5531903999970 is 799993091355.
It is a junction number, because it is equal to n+sod(n) for n = 5531903999895 and 5531903999904.
It is not an unprimeable number, because it can be changed into a prime (5531903999971) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 846732 + ... + 3432311.
It is an arithmetic number, because the mean of its divisors is an integer number (414902524806).
Almost surely, 25531903999970 is an apocalyptic number.
5531903999970 is an abundant number, since it is smaller than the sum of its proper divisors (7744976793822).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5531903999970 is a wasteful number, since it uses less digits than its factorization.
5531903999970 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4322146.
The product of its (nonzero) digits is 93002175, while the sum is 69.
The spelling of 5531903999970 in words is "five trillion, five hundred thirty-one billion, nine hundred three million, nine hundred ninety-nine thousand, nine hundred seventy".
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