Base | Representation |
---|---|
bin | 11001001010010000000001… |
… | …00001100101101100110111 |
3 | 21020220021122221111020122001 |
4 | 30211020000201211230313 |
5 | 24222442242020342442 |
6 | 313401121411320131 |
7 | 14440204622155432 |
oct | 1445100041455467 |
9 | 236807587436561 |
10 | 55327777512247 |
11 | 166a1419016a39 |
12 | 6256a888b0047 |
13 | 24b4505404a06 |
14 | d93c432c8819 |
15 | 65e3084a92b7 |
hex | 325200865b37 |
55327777512247 has 2 divisors, whose sum is σ = 55327777512248. Its totient is φ = 55327777512246.
The previous prime is 55327777512191. The next prime is 55327777512281. The reversal of 55327777512247 is 74221577772355.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55327777512247 is a prime.
It is a super-2 number, since 2×553277775122472 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55627777512247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27663888756123 + 27663888756124.
It is an arithmetic number, because the mean of its divisors is an integer number (27663888756124).
Almost surely, 255327777512247 is an apocalyptic number.
55327777512247 is a deficient number, since it is larger than the sum of its proper divisors (1).
55327777512247 is an equidigital number, since it uses as much as digits as its factorization.
55327777512247 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 201684000, while the sum is 64.
The spelling of 55327777512247 in words is "fifty-five trillion, three hundred twenty-seven billion, seven hundred seventy-seven million, five hundred twelve thousand, two hundred forty-seven".
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