Base | Representation |
---|---|
bin | 110011100010000111… |
… | …000001110111010101 |
3 | 12021211020222202212121 |
4 | 303202013001313111 |
5 | 1401310233213023 |
6 | 41230352215541 |
7 | 3666130412131 |
oct | 634207016725 |
9 | 167736882777 |
10 | 55333101013 |
11 | 21515102853 |
12 | a882b3a5b1 |
13 | 52aa9189b8 |
14 | 296cb403c1 |
15 | 168cb97d5d |
hex | ce21c1dd5 |
55333101013 has 2 divisors, whose sum is σ = 55333101014. Its totient is φ = 55333101012.
The previous prime is 55333101007. The next prime is 55333101041. The reversal of 55333101013 is 31010133355.
55333101013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 55209491089 + 123609924 = 234967^2 + 11118^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55333101013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55333101073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27666550506 + 27666550507.
It is an arithmetic number, because the mean of its divisors is an integer number (27666550507).
Almost surely, 255333101013 is an apocalyptic number.
It is an amenable number.
55333101013 is a deficient number, since it is larger than the sum of its proper divisors (1).
55333101013 is an equidigital number, since it uses as much as digits as its factorization.
55333101013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2025, while the sum is 25.
Adding to 55333101013 its reverse (31010133355), we get a palindrome (86343234368).
The spelling of 55333101013 in words is "fifty-five billion, three hundred thirty-three million, one hundred one thousand, thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •