Base | Representation |
---|---|
bin | 11001001011010111010111… |
… | …00000000111011010110101 |
3 | 21021000221112021110100012201 |
4 | 30211223223200013122311 |
5 | 24224104212323311242 |
6 | 313430454212144501 |
7 | 14443032030605101 |
oct | 1445535340073265 |
9 | 237027467410181 |
10 | 55366079510197 |
11 | 167066935469a5 |
12 | 6262398008131 |
13 | 24b7cca75a221 |
14 | d95a38170901 |
15 | 6602ead844b7 |
hex | 325aeb8076b5 |
55366079510197 has 2 divisors, whose sum is σ = 55366079510198. Its totient is φ = 55366079510196.
The previous prime is 55366079510123. The next prime is 55366079510213. The reversal of 55366079510197 is 79101597066355.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51826767244561 + 3539312265636 = 7199081^2 + 1881306^2 .
It is a cyclic number.
It is not a de Polignac number, because 55366079510197 - 243 = 46569986487989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55366079510597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27683039755098 + 27683039755099.
It is an arithmetic number, because the mean of its divisors is an integer number (27683039755099).
Almost surely, 255366079510197 is an apocalyptic number.
It is an amenable number.
55366079510197 is a deficient number, since it is larger than the sum of its proper divisors (1).
55366079510197 is an equidigital number, since it uses as much as digits as its factorization.
55366079510197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 53581500, while the sum is 64.
The spelling of 55366079510197 in words is "fifty-five trillion, three hundred sixty-six billion, seventy-nine million, five hundred ten thousand, one hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •