55401203131 has 2 divisors, whose sum is σ = 55401203132. Its totient is φ = 55401203130.

The previous prime is 55401203111. The next prime is 55401203147. The reversal of 55401203131 is 13130210455.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-55401203131 is a prime.

It is a super-2 number, since 2×55401203131² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 55401203096 and 55401203105.

It is not a weakly prime, because it can be changed into another prime (55401203111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27700601565 + 27700601566.

It is an arithmetic number, because the mean of its divisors is an integer number (27700601566).

Almost surely, 2^55401203131 is an apocalyptic number.

55401203131 is a deficient number, since it is larger than the sum of its proper divisors (1).

55401203131 is an equidigital number, since it uses as much as digits as its factorization.

55401203131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 55401203131 its reverse (13130210455), we get a palindrome (68531413586).

The spelling of 55401203131 in words is "fifty-five billion, four hundred one million, two hundred three thousand, one hundred thirty-one".