Base | Representation |
---|---|
bin | 11001001100101001001011… |
… | …11111101011000101000101 |
3 | 21021012010220220102120220021 |
4 | 30212110211333223011011 |
5 | 24230314200144043323 |
6 | 313503001334335141 |
7 | 14446145500262236 |
oct | 1446244577530505 |
9 | 237163826376807 |
10 | 55410010534213 |
11 | 16723287457515 |
12 | 626a9b84ba4b1 |
13 | 24bc1ac0607aa |
14 | d97c0485908d |
15 | 66151ca1905d |
hex | 326525feb145 |
55410010534213 has 2 divisors, whose sum is σ = 55410010534214. Its totient is φ = 55410010534212.
The previous prime is 55410010534199. The next prime is 55410010534223. The reversal of 55410010534213 is 31243501001455.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 55393753519204 + 16257015009 = 7442698^2 + 127503^2 .
It is a cyclic number.
It is not a de Polignac number, because 55410010534213 - 213 = 55410010526021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55410010534223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27705005267106 + 27705005267107.
It is an arithmetic number, because the mean of its divisors is an integer number (27705005267107).
Almost surely, 255410010534213 is an apocalyptic number.
It is an amenable number.
55410010534213 is a deficient number, since it is larger than the sum of its proper divisors (1).
55410010534213 is an equidigital number, since it uses as much as digits as its factorization.
55410010534213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 55410010534213 its reverse (31243501001455), we get a palindrome (86653511535668).
The spelling of 55410010534213 in words is "fifty-five trillion, four hundred ten billion, ten million, five hundred thirty-four thousand, two hundred thirteen".
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